-2x^2+12^2-10=0

Solution for -2x^2+12^2-10=0 equation:

-2x^2+12^2-10=0

We add all the numbers together, and all the variables

-2x^2+134=0

a = -2; b = 0; c = +134;
Δ = b2-4ac
Δ = 02-4·(-2)·134
Δ = 1072
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1072}=\sqrt{16*67}=\sqrt{16}*\sqrt{67}=4\sqrt{67}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{67}}{2*-2}=\frac{0-4\sqrt{67}}{-4}
=-\frac{4\sqrt{67}}{-4}
=-\frac{\sqrt{67}}{-1}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{67}}{2*-2}=\frac{0+4\sqrt{67}}{-4}
=\frac{4\sqrt{67}}{-4}
=\frac{\sqrt{67}}{-1}
$